A new poster has been released for the students who want to prepare for NET JRF. As it is mentioned in poster, batch is going to start on 6 June 2019. Teaching and discussion time for this batch is 8 o'clock in morning. And teachers will be Dr Vandana Kumari and team.
Details in short are as follows:
Batch starting date: 6 June 2019
Time: 8:00 am
Purpose: to help students who want to appear for NET
Subject: Physics
Target : 100% students JRF in first chance.
Venue:
SPAN EDUCATION, 1st floor,
Above Bhargava Opticals,
Opposite Jaipur Hospital,
Gopalpura Puliya,
Tonk Road, Jaipur
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Introduction of NET-JRF:
- NET : National Eligibility Test
- JRF : Junior Research Fellowship
For the subject of physics (all subjects in science) there is a Joint CSIR-UGC test named NET for JRF. This is a common national level test. If you get good marks, you will get a certificate for NET, some people call it LS means you will be eligible for applying lectureship in colleges in India. CSIR conducts this exam two times in a year. For physics students, you should have been enrolled in MSc from any college or university and supposed to be complete your masters within two years. Since, in India, MSc programs are only for two years if you are not dropping time in between.
You can find all details about this exam at : http://csirhrdg.res.in
If you want to see the details of next exam which is going to be held in this month (16 June 2019), please see the followings:
CSIR-UGC (NET) exam for award of JRF and eligibility for lectureship have a single paper test which includes only multiple choice questions (MCQ). This question paper have three parts:
Part A: This part shall carry 20 questions pertaining to General Science, Quantitative Reasoning & Analysis and Research aptitude. The candidates shall be required to answer any 15 questions. Each question shall be of two marks. The total marks allocated to this section be 30 out of 200.
Part B: This part shall contain 25 MCQs generally covering the topics given in the part A (core) of syllabus. Each question shall be of 3.5 marks. The total marks allocated to this section shall be 70 out of 200. Candidates are required to answer any 20 questions.
Part C: This part shall contain 30 questions from part 'B' (advanced) and part 'A' that are designed to test a candidate's knowledge of scientific concepts and/or application of the scientific concepts. The questions shall be of analytical nature where a candidate is expected to apply the scientific knowledge to arrive at the solution to the given scientific problem. A candidate shall be required to answer any 20. Each question shall be of 5 marks. The total marks allocated to this section shall be 100 out of 200.
Above material is copied from csir website.
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